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1.0 g of metal nitrate gave 0.86 g of metal carbonate. Calculate the Equivalent weight of metal. |
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Answer» Let the equivalent weight of metal `=E` Ew of metal nitrate`=Ew of M+EwNO_3^(ɵ)=E+62` Equivalent weight of metal carbonate `=` Equivalent weight of metal `+` Equivalent weight of `CO_3^(2-)` `=E+(60)/(2)=E+30` `therefore("Ew of M nitrate")/("Ew of M carbonate")=("Weight of M nitrate")/("weight of M sulphate")` `(E+62)/(E+30)=(1.0)/(0.86)` `thereforeE=166.57` |
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