1.

1.00 g of a non electrolyte solute ( molar mass 250 " g mol"^(-1)) was dissolved in 51.2 g of benzene. If the freezing point depression constant, K_(f) of benzene is 5*12 K kg "mol"^(-1), the freezing point of benzene will be lowered by

Answer»

0.3 K
0.5 K
0.2 K
0.4 K

Solution :`DELTA T_(f)=(K_(f)xx 1000 xx W_(2))/(M_(2)xxW_(1))`
`(5*12xx1000xx1)/(51*2xx250)=0*4`.


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