1.

1.00 gm of a non-electrolyte solute dissolved in 50 gm of benzene lowered the freezing point of benzene by 0.40 K. K_(f) for benzene is 5.12 kg mol^(-1). Molecular mass of the solute will be

Answer»

`256 g mol^(-1)`
`2.56 g mol^(-1)`
`512xx10^(3)g mol^(-1)`
`2.56xx10^(4)g mol^(-1)`

Solution :By USING, `m=(K_(f)xx1000xx W)/(DELTA T_(f)xx W_("SOLVENT")(gm))=(5.12xx1000xx1)/(0.40xx50)`
= 256 gm/mol
Hence, molecular mass of the SOLUTE `= 256 gm mol^(-1)`


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