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1.00 `l` sample of a mixture of `CH_(4) (g)` & `O_(2)(g)` measured at `25^(@)C` & `740` torr was allowed to react at constant pressure in a calorimeter which together with its contents had a heat capacity of 1260 Cal/K. The Complete combustion of methane to `CO_(2)` & `H_(2)O` caused a temperature rise, in the Calorimeter, of 0.667 K. What was the mole percent of `CH_(4)` in the original mixture ? `DeltaH_("comb")^(@) (CH_(4))=-215" k Cal mol"^(-1)`. |
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Answer» Correct Answer - `9.82" mol"% CH_(4)` Total energy released `=1260xx0.667=840.42 cal` Moles of `CH_(4) =(840.42)/(215.10^(3)) =3.9xx10^(-13)` Calculate V of `CH_(4)` By applying `PV=nRT` `V=0.098246 L` `%` moles of `CH_(4)=(0.098246)/(1) xx100=9.82 %` |
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