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The standard heat of formation values of `SF_(6)(g), S(g)`, and `F(g)` are `-1100, 275`, and `80 kJ mol^(-1)`, respectively. Then the average `S-F` bond enegry in `SF_(6)` |
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Answer» Given, `S_((s))+3F_(2(g))rarr SF_(6),DeltaH=-1100kJ ....(1)` `S_((s)) rarr S_((g)),DeltaH=275kJ ...(2)` `(1)/(2)F_(2(g))rarr F_((g)), DeltaH=80kJ ..(3)` To get `SF_(6(g))rarr S_((g))++6F_((g)),,` we can proceed as `eq. (2)+6xxeq.(3)-eq.(1)` `SF_(6(g))rarrS_((g))+6F_((g)),DeltaH=1855kJ` Thus, average bond energy `=(1855)/(6)=309.17` |
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