1 1/2 moles of oxygen combine with Aluminimum to form AL O, then weigh

1.	1 1/2 moles of oxygen combine with Aluminimum to form AL O, then weight of Aluminium metal used in thereaction is (al = 27) -2A1+ 02 â>A1,02(440 cm
Answer» The balanced reaction is 4Al + 3O2= 2Al2O3 3moles of O2requires 4 moles of Al0.5 moles of O2requires = 4 X 0.5/3 = 2/3 moles of Al Mass of 2/3 mol of Al = 2/3 mol X 27g/mol= 18 g Where 27 is the mass of 1 mole Al Answer:18gm

1 1/2 moles of oxygen combine with Aluminimum to form AL O, then weight of Aluminium metal used in thereaction is (al = 27) -2A1+ 02 â>A1,02(440 cm

Answer»

The balanced reaction is 4Al + 3O2= 2Al2O3

3moles of O2requires 4 moles of Al0.5 moles of O2requires = 4 X 0.5/3 = 2/3 moles of Al

Mass of 2/3 mol of Al = 2/3 mol X 27g/mol= 18 g

Where 27 is the mass of 1 mole Al

Answer:18gm