1.

1.1 mole of A are mixed with 2.2 mole of B and the mixture is then kept in a 1 L vessel till the equilibrium :A+2B hArr 2C+Dis reached.At equilibrium 0.2 moles of C are formed.The equilibrium constant for the reaction is :

Answer»

`0.001`
`0.002`
`0.003`
`0.004`

SOLUTION :`K=([C]^(2)[D])/([A][B]^(2))`
`[C]=0.2[D]=0.1, [A] =1.1-0.1=1.0`,
`[B]=2.2-0.2=2.0`
`therefore K=((0.2)^(2)(0.1))/((1.0)(2.0)^(2))=0.001`


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