1.16 g CH_(3)(CH_(2))_(n)COOH was burnt in excess air and the resultan – InterviewSolution

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1.	1.16 g CH_(3)(CH_(2))_(n)COOH was burnt in excess air and the resultant gases (CO_(2) and H_(2)O) were passed through excess NaOH solution. The resulting solution was divided in two equal parts. One part requires 50 mL of 1 N HCl for neutralization using phenolphthalein as indicator. Another part required 80 mL of 1 N HCl for neutralization using methyl orange as indicator. What is the value of n
Answer» 4 3 2 1 Answer :A

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