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1). 182). 153). 104). 12 |
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Answer» MINIMUM NUMBER of rows = Maximum number of balls in each row ∴ HCF of 36, 54 and 90 = 18 ∴ Minimum number of rows = $(\frac{{36}}{{18}} + \;\frac{{54}}{{18}} + \;\frac{{90}}{{18}} = 2 + 3 + 5 = 10)$ |
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