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Unit's digits of a 2 digit number is 5 more than the ten's digit, and if we put the digits of the number in reverse order, the new number is 4 less than twice the original number. The number is :-1). 272). 493). 724). 38 |
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Answer» Let the digits of the number be a and b. ∴ the number is 10A + b Given Unit's digits of a 2 digit number is 5 more than the ten's digit ∴ b = 5 + a-----[1] On reversing the digits number OBTAINED = 10b + a Now, this number is 4 less than TWICE the original number ∴ 2(10a + b) – (10b + a) = 4 ⇒ 19a – 8b = 4 -----[2] Putting the value of b = 5 + a from equation [1] in equation [2] ⇒ 19a – 40 – 8a = 4 ⇒ 11a = 44 ⇒ a = 44/11 = 4 ∴ b = 5 + a = 5 + 4 = 9 The original number is 49 |
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