1.

`1^(2). C_(1) - 2^(2) . C_(2)+ 3^(2). C_(3) -4^(2)C_(4) + ...+ (-1).""^(n-2)n^(2)C_(n)=`

Answer» Correct Answer - a
We have ,
`(1 + x)^(n) = C_(0) + C_(1) x + C_(2) x^(2) + ... + C_(n) x^(n)`
Putting x = -1 on both sides, we get
`C_(0) - C_(1) + C_(2) - C_(3) + ...+C_(n) = 0` .


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