1.

""_(1)^(2)H+""_(1)^(2)H to ""_(2)^(3)He+X Q. Identify the particle X resulting from the nuclear reaction show above.

Answer»

Positron
Electron
Proton
NEUTRON

Solution :To balance the superscripts, we write `2+2=3+A`, and GET A=1, now, to balance the SUBSCRIPTION, we write 1+1=2+Z, so Z=2. therefore, the particle X has a mass number of 1 and a charge of 0, it's a neutron.


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