1.

1). 2002). 3003). 4004). 600

Answer»

LET the MAXIMUM marks of the examination be x.

Passing marks of the EXAM = 105 - 6 = 99

∴ 33% of x = 99

$(\begin{ARRAY}{l} \Rightarrow \frac{{33}}{{100}} \times x = 99\\ \Rightarrow x = \frac{{99{\rm{\;}} \times 100}}{{33}} = 300\end{array})$ 

Hence, maximum marks of the exam is 300.



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