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1). 2002). 3003). 4004). 600 |
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Answer» LET the MAXIMUM marks of the examination be x. Passing marks of the EXAM = 105 - 6 = 99 ∴ 33% of x = 99 $(\begin{ARRAY}{l} \Rightarrow \frac{{33}}{{100}} \times x = 99\\ \Rightarrow x = \frac{{99{\rm{\;}} \times 100}}{{33}} = 300\end{array})$ Hence, maximum marks of the exam is 300. |
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