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1.25g of a sample chlorine in 25 mL of water and 25 mL of which are treated with KI solution . The iodine so liberatedrequired 12.5 of which are treated with KI solution . The iodine so liberated required 12.5 mL of N/25 hypo solution in titration . Find the percentage of chlorine available from the sample of bleaching powder . |
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Answer» Solution :m.e of available CHLORINE in 25 mLbleachingpowder solution = m.e of iodine liberated = m.e of hypo solution ` = 1/25 xx 12.5 = 0.5` ` :. ` m.e of available chlorine in 100 mL = `(0.5 xx 100)/25 = 2 ` ` :. ` eq of available chlorine ` = 2/100` wt . of available chlorinein `1.25 ` of bleaching powder ` = (0.2)/1000 xx 35.5 = 0.071` g ( eq. wt of CHLORNE = 35.5) ` :. ` PERCENTAGE of available chlorine ` = (0.071)/(1.25) xx 100` ` = 5.68 % ` |
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