1.

1.25g of a sample chlorine in 25 mL of water and 25 mL of which are treated with KI solution . The iodine so liberatedrequired 12.5 of which are treated with KI solution . The iodine so liberated required 12.5 mL of N/25 hypo solution in titration . Find the percentage of chlorine available from the sample of bleaching powder .

Answer»

Solution :m.e of available CHLORINE in 25 mLbleachingpowder solution
= m.e of iodine liberated
= m.e of hypo solution
` = 1/25 xx 12.5 = 0.5`
` :. ` m.e of available chlorine in 100 mL = `(0.5 xx 100)/25 = 2 `
` :. ` eq of available chlorine ` = 2/100`
wt . of available chlorinein `1.25 ` of bleaching powder
` = (0.2)/1000 xx 35.5 = 0.071` g ( eq. wt of CHLORNE = 35.5)
` :. ` PERCENTAGE of available chlorine ` = (0.071)/(1.25) xx 100`
` = 5.68 % `


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