1.

1−2ab−(a2+b2)=?(a) (1+a−b)(1+a+b)(b) (1+a+b)(1−a+b)(c) (1+a+b)(1−a−b)(d) (1+a−b)(1−a+b)

Answer»

1−2ab−(a2+b2)=?(a) (1+a−b)(1+a+b)(b) (1+a+b)(1−a+b)(c) (1+a+b)(1−a−b)(d) (1+a−b)(1−a+b)



Discussion

No Comment Found