1.

1.30 Lit N_2 gas at 2atm and 300K in a container is exposed to 4g of solid surface. After complete adsorption the pressure of N_2 is reduced by 30% calculate the value of x/m

Answer»

0.22 
0.56 
0.32 
0.43

Solution :PRESSURE is reduced by 30% `=(2 XX 30)/(100) 0.6 ATM`
`PV = W/(MRT) , 0.6 xx 1.3 = W/28 xx 0.0821 xx 300 , wt = 0.8732 , x/m = (0.8732)/(4) = 0.22`


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