(1) 35%6.A gaseous mixture contains CH, and C.H in equimolecular propo

1.	(1) 35%6.A gaseous mixture contains CH, and C.H in equimolecular proportion. The weight oL16 in equimolecular proportion. The weight of 2.24 litres of this mixture(4) 23 gat NTP is :(1) 4.6 g(2)1.6 g(3) 2.3 g
Answer» Suppose we take 1 mole of CH4 Weight=16gm And 1mole C2H6 weight =30gm Now, 1 mole of both CH4 and C2H6 occupy 22.4L Therefore when mixed Total weight of mixture=16+30=46 Total volume of mixture=22.4+22.4=44.8L 44.8L of mixture weigh 46g So,2.24L of mixture weighs=( 46÷44.8)×2.24=2.3g

(1) 35%6.A gaseous mixture contains CH, and C.H in equimolecular proportion. The weight oL16 in equimolecular proportion. The weight of 2.24 litres of this mixture(4) 23 gat NTP is :(1) 4.6 g(2)1.6 g(3) 2.3 g

Answer»

Suppose we take 1 mole of CH4

Weight=16gm And 1mole C2H6

weight =30gm

Now, 1 mole of both CH4 and C2H6 occupy 22.4L

Therefore when mixed Total weight of mixture=16+30=46

Total volume of mixture=22.4+22.4=44.8L

44.8L of mixture weigh 46g

So,2.24L of mixture weighs=( 46÷44.8)×2.24=2.3g