1.

1.5 % Urea solution and 5.25% unknown substance's solutions are isotonic. The density of both the solutions are 1 gm//cm^(3) then what is the molecular weight of unknown substance ?

Answer»

90.0 gram/mole
115.0 gram/mole
1050.0 gram/mole
210.0 gram/mole

SOLUTION :For isotonic solution `(W_("unknown"))/(M_("unknown"))=(W_("UREA"))/(M_("urea"))`
`M_("unknown")=(5.25xx60)/(1.5)=210` gram/mole


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