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1.6 L of helium gas at STP is adiabatically compressed to 0.2 L. Taking the initial temperature to be 27∘C, the work done in the process is[Take R=8.314 J/mol K]

Answer» 1.6 L of helium gas at STP is adiabatically compressed to 0.2 L. Taking the initial temperature to be 27C, the work done in the process is

[Take R=8.314 J/mol K]


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