1.

1.615 g of anhydrous ZnSO_(4) was placed in moist air. After a few days, its mass was found to be 2.875 g. What is the molecular formula of the hydrated salt? (At. Mass : Zn = 65.5, S = 32, O = 16)

Answer»

Solution :Molecular MASS of ANHYDROUS `ZnSO_(4)=65.5+32+64=161.5`
1.615 G of anhydrous `ZnSO_(4)` combine with `H_(2)O=2.875-1.615g=1.260g`
`therefore"1.615 g of anhydrous "ZnSO_(4)" will combine with "H_(2)O=(1.260)/(1.615)xx161.5g`
`=126g=(126)/(18)"moles = 7 moles"`
Hence, formula of the hydrated salt = `ZnSO_(4).7H_(2)O.`


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