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1.67 g mixture of Al and Zn was completely dissolved in acid and evolved 1.69 L of `H_2` at STP. Calculate the weight Al and Zn in the mixture. |
Answer» Let x and y be the weights of Al and Zn in the mixture. `x+y=1.67` .. (i) " Eq of "`Al+Eq` of `Zn= Eq` of `H_2` `((a)/((27)/(3))+(b)/((65)/(2)))=(1.69)/((22.4)/(2)) ` …(ii) Solving equation (i) and (ii) we get `x=1.25 g` `y=0.42` |
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