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1.725 g of a metal carbonate is mixed with 300 ml of N/10 HCl. 10 ml of N/2 sodium hydroxide were required to neutralise excess of acid. Calculate the equivalent mass of metal carbonate.

Answer» 1.725 g of a metal carbonate is mixed with 300 ml of N/10 HCl. 10 ml of N/2 sodium hydroxide were required to neutralise excess of acid. Calculate the equivalent mass of metal carbonate.


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