1.

1.78 g of an optically active L-amino acid (A) is treated with NaNO_2//HCl at 0^(@) C. 448 cm^(3) of nitrogenwas at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein is

Answer»

`36,500 G "mol"^(-1)`
`34,500 g " mol"^(-1)`
`35,400 g " mol"^(-1)`
`35,600 g "mol"^(-1)`

Solution :`1.78g - 448 CM^(3)`
`?-22400 cm^(3)`
Mol mass of L - amino acid `=1.78 XX (22400)/(448) = 89`
`:. ` Mol mass of protein is
100-0.25
`?-89`
`= (100 xx 89)/(0.25 )` = 35,600 g / mol


Discussion

No Comment Found

Related InterviewSolutions