1.

1). 8002). 9003). 7504). 1000

Answer»

Let, Cost Price of the first table = Rs. y

∴ Cost price of the other table = Rs. (1800 - y) [? Purchase price of TWO tables = Rs.1800]

According the problem,

Selling price of the first table = Rs. y × 4/5

Selling price of the SECOND table = Rs. ((1800 - y) × 5) /4

∴ $(\frac{{4y}}{5}\; + \;\frac{{\left( {1800 - y} \right)\; \times \;5}}{4})$ = 1800 + 90 [? He made an overall gain of Rs. 90]

Or, $(\frac{{4y}}{5} - \frac{{5y}}{4})$ = 1890 - 2250

Or, (16y - 25y) /20 = - 360

Or, - 9y = - 360 × 20

Or, y = 7200/9

⇒ y = 800

∴ Cost of the first table = Rs. 800

Cost of the other table = Rs. (1800 - 800) = Rs. 1000

∴ Cost of the LESSER valued chair = Rs. 800



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