InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Coconuts were purchased at Rs. 150 per hundred and sold at Rs. 2 per coconut. If 2000 coconuts were sold. What was the total profit made?1). Rs. 5002). Rs. 10003). Rs. 15004). Rs. 2000 |
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Answer» CP of 100 coconuts = Rs 150 ∴ CP of 2000 coconuts = Rs 150 × 2000/100 = Rs 3000 ? SP of 1 coconut = Rs 2 ∴ SP of 2000 coconuts = Rs 2 × 2000 = Rs 4000 ⇒ Profit = SP – CP = 4000 – 3000 = Rs 1000 |
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| 2. |
1). 52). 6.253). 7.54). 12.5 |
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Answer» Let marked price be M. The marked price of an ITEM is Rs. 40 more than the selling price. The cost price of this item is 5/8th of marked price. ⇒ Selling price = M – 40 And, cost price = 5M/8 Profit percentage = 50% Selling price = Cost Price × (1 + Profit Percentage/100) ⇒ M - 40 = 5M/8 × (1 + 50/100) ⇒ 8M – 320 = 7.5M ⇒ M = 320/0.5 = 640 We KNOW, Selling price = Marked price × (1 – DISCOUNT percentage/100) ⇒ 640 – 40 = 640 × (1 - Discount percentage/100) ⇒ Discount percentage = 100 × (1 – 600/640) = 6.25% |
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| 3. |
The profit earned after selling an article for Rs. 2,154 is the same as loss incurred after selling the article for Rs. 1, 692. What is the cost price of the article?1). Rs. 1,9232). Rs. 1,7233). Rs. 1,6894). Rs. 1,889 |
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Answer» Let, x be the cost PRICE of the article ∴ PROFIT earned after SELLING the article for Rs. 2,154 is = Rs. (2154 – x) Again, Loss incurred after selling the article for Rs. 1,692 is = Rs. (x – 1692) ACCORDING to the question, 2154 – x = x – 1692 ⇒ 2x = 3846 ⇒ x = 3846/2 = Rs. 1923 |
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| 4. |
If the shopkeeper keeps the marked price of an article to Rs. 2500 and says to give two successive discounts of 15% and 20% and still manages to earn a profit of 10%, find the cost price of the article?1). Rs. 1525.452). Rs. 1545.453). Rs. 1595.654). Rs. 1625.45 |
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Answer» LET the cost price be x Marked price of article = Rs. 2500 Price after FIRST discount = (85/100) × 2500 = Rs. 2125 Price paid by PURCHASER = (80/100) × 2125 = Rs. 1700 Profit = 10% ⇒ x + (10/100) × x = 1700 ⇒ x = Rs. 1545.45 ∴ Cost price = Rs. 1545.45 |
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| 5. |
P sold a pen each to Q and R at 10% and 20% profits, respectively. Q sold pen to S at 15% profit. At what profit should R sell the pen to S so that S would have bought both pens at same price? (in %)1). 5.422). 6.163). 6.674). 7.2 |
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Answer» <P>P sold a pen each to Q and R at 10% and 20% PROFITS, respectively. We know, Selling PRICE = Cost Price × (1 + Profit Percentage/100) Cost price for S from Q = Cost price of P × (1 + 10/100) × (1 + 15/100) = 1.265 × cost price of P For R to sell to S at same price, let profit percentage be T%. ⇒ Cost price of P × (1 + 20/100) × (1 + T/100) = 1.265 × cost price of P ⇒ T = 5.42 ∴ Profit should be 5.42%. |
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| 6. |
In a business, A and B invested a total amount of Rs. 36,000, with A investing five times B. After eight months, C invested Rs. 40,000 and A withdrew Rs. 10,000. If A’s share after a year of business was Rs. 16,000, then what is C’s share?1). Rs. 3,6002). Rs. 8,0003). Rs. 14,7804). Rs. 17,900 |
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Answer» Let B’s INITIAL investment be x. ∴ A’s initial investment is 5x. 5x + x = RS. 36,000 ∴ x = Rs. 6,000 ∴ 5x = Rs. 30,000 Ratio of their share in profit = Ratio of their investments ⇒ 30000 × 8 + 20000 × 4 ? 6000 × 12 ? 40000 × 4 = Rs. 1,60,000 Thus, ratio of their investments = 320000 ? 72000 ? 160000 = 40 ? 9 ? 20 Profit earned after a year = x A’s share = 16000 = (40/69) × x ∴ x = Rs. 27,600 ∴ C’s share = (20/69) × 27600 = 8000 ∴ C’s share is Rs. 8,000. |
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| 7. |
Rahul invested Rs. 6000 in a business. After 4 months Aniket joined him in the business and invested Rs. 10000. If at the end of the year they received profit of Rs. 19000; then find the share of Rahul’s profit.1). Rs. 60002). Rs. 72003). Rs. 81004). Rs. 9000 |
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Answer» Rahul’s part of investment ? Aniket’s part of investment = Rs. 6000 × 12 months ? Rs. 10000 × 8 months ∴ Rahul’s part of investment ? Aniket’s part of investment = 72000 ? 80000 = 9 : 10 ∴ Profit of Rahul = (9/19) × 19000 = 9000 Rs. ∴ Rahul will RECEIVE Rs. 9000 profit. |
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| 8. |
1). 35%2). 38%3). 42%4). 44% |
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Answer» Let the cost price be Rs. 100 Gain REQUIRED = 15% ∴ Selling price = Rs. 115 Then, discount = 20% of Rs. x ⇒ Rs. (x × 20/100) = Rs. x/5 ∴ selling price = (Marked Price) - (discount) ⇒ Rs. {x - (x/5)} = Rs. 4x/5 ∴ 4x/5 = 115 ⇒ x = {115 × (5/4)} = 143.75 ≈ 144 ∴ Marked price = Rs. 144 Hence, the marked price is 44% above cost price. |
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| 9. |
Rakesh on selling a lamp for Rs. 450 bears a loss of 20%. To earn a profit of 20%, he should sell the lamp for 1). 6752). 6003). 6254). 680 |
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Answer» Let the C.P be X ⇒ x – (20% x) = 450 ⇒ (80/100)x = 450 ⇒ x = 562.5 ∴ REQUIRED selling PRICE = 562.5 + (20% of 562.5) = 675 |
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| 10. |
Quantity B∶ Number of months after which B made his 3rd investment if B invests Rs. 1500 at beginning of every quarter and finally he invests Rs. 500 after 11 months1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A = Quantity B or no relation4). Quantity A ≤ Quantity B |
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Answer» As both receives EQUAL profits in the year. It means that their capital RATIO is 1 ? 1 Let A’s 3rd INVESTMENT is used for x months Capital of A? (1000 × 12) + (1500 × 9) + (2000 × x) + (4 × 2500) ⇒ 12000 + 13500 + 2000x + 10000 ⇒ 35500 + 2000x Capital of B? (1500 × 12) + (1500 × 9) + (1500 × 6) + (1500 × 3) + (500 × 1) ⇒ 18000 + 13500 + 9000 + 4500 + 500 ⇒ Rs. 45500 According to the question, 35500 + 2000x = 45500 ⇒ 2000x = 45500 – 35500 ⇒ 2000x = 10000 ⇒ x = 10000/2000 ⇒ x = 5 3rd investment of A is being used for 5 months It means that A has made his 3rd investment after 7 months i.e. 12 – 5 B has made his 3rd investment at the beginning of 3rd quarter i.e. after 6 months ∴ Quantity I is more than Quantity II |
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| 11. |
If a merchant offers a discount of 40% on the marked price of his goods and thus ends up selling at cost price, what was the % markup? 1). 42.85%2). 58.54% 3). 66.67%4). 79.85% |
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Answer» If the MERCHANT offers a discount of 40% on the marked PRICE, then the goods are sold at 60% of the marked price. ∴ selling @ 40% discount = 60% of marked price (M) = COST price (C). ⇒ (60/100) × M = C ∴ M = (100/60) × C = 1.666667 × C ∴ % MARKUP = 66.67% |
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| 12. |
Three partners invest certain amount in a business. Sunil invested Rs. 20000; Anil invested Rs. 30000 while Anita invested Rs. 10000. At the end of 6 months they received profit of Rs. 10000. Find the percentage profit received by Anita.1). 12.25%2). 16.67%3). 17.25%4). 18.50% |
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Answer» From given data- Three partners Sunil, Anil & Anita invested Rs. 20000, Rs. 30000 & Rs. 10000 respectively. ∴ their RATIO of invested amount is 20000 ? 30000 ? 10000 ∴ their ratio of invested amount = 2 ? 3 ? 1 ∴ Partners will receive Rs. 10000 profit in the ratio of 2 ? 3 ? 1 Let the common multiplication CONSTANT be X. ∴ Sunil, Anil & Anita will receive profit as 2X, 3X & X respectively. For Anita- She will receive X parts of profit from 6X parts. ∴ Profit percent received by Anita = (X/6X) × 100 = 16.67% |
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| 13. |
Marked price of a shirt is Rs. 1000. If shopkeeper declares successive discount on shirt of 15% & 25%. Find the selling price of the shirt.1). Rs. 475.252). Rs. 5003). Rs. 515.54). Rs. 637.5 |
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Answer» Initial marked price of SHIRT is Rs. 1000 First discount = 15% New selling price = Rs. 850 Successive discount = 25% Final selling price = 850 - (25/100) × 850 = Rs. 637.5 |
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| 14. |
Arun bought an item and spent Rs. 110 on its repairs. He then sold it to Salman at a profit of 20% Salman sold it to Tarun at a loss of 10% Tarun finally sold it for Rs. 1188 at a profit of 10%. How much did Arun pay for the article?1). Rs. 8902). Rs. 7803). Rs. 8404). Rs. 1000 |
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| 15. |
A fruit seller sells 8 oranges at cost price of 9. The profit per cent is1). \(12\frac{1}{2}\)2). \(11\frac{1}{9}\)3). \(5\frac{{15}}{{17}}\)4). \(8\frac{2}{3}\) |
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Answer» Let the cost PRICE of ONE orange = c ∴ Cost price of 8 oranges = 8c Given, Selling price of 8 oranges = cost price of 9 oranges = 9c PROFIT % = $(\FRAC{{selling\;price\;-\;cost\;price}}{{cost\;price}}\; \times \;100\;\% )$ ⇒Profit% $(= \frac{{9c\;-\;8c}}{{8c}} \times 100\;\% )$ ⇒ Profit % $(= \frac{{100}}{8}\%= 12\frac{1}{2}\;\% )$ |
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| 16. |
P, Q, R and S invested Rs. 3500 each in a partnership. After 6 months, P doubled his investment. Q and R invested for only 4 months of the year. S kept his investment for entire year. After a year, if Q got a profit of Rs. 200, then what was the total profit?1). Rs. 19002). Rs. 20003). Rs. 21004). Rs. 2400 |
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Answer» <P>After 6 months, P doubled his investment. ⇒ P invested Rs. 3500 for 6 months and Rs. 7000 for other 6 months. Q and R invested for only 4 months of the year. The ratio of PROFITS of P, Q, R and S = (6 × 3500 + 6 × 7000) : (4 × 3500) : (4 × 3500) : (12 × 3500) = 9 : 2 : 2 : 6 Q got a profit of Rs. 200. So, TOTAL profit = ((9 + 2 + 2 + 6)/2) × Rs. 200 = Rs. 1900 |
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| 17. |
The selling price will be least under which Plan?1). Plan 12). Plan 23). Plan 34). Plan 4 |
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Answer» Let the marked price be Rs. X. Sell Price = Marked Price (1 − Discount %) Selling Price in Plan 1 = (1 - 0.15) × (1 - 0.20) × x = 0.68x Selling Price in Plan 2 = (1 - 0.14) × (1 - 0.21) × x = 0.6794x Selling Price in Plan 3 = (1 - 0.10) × (1 - 0.25) × x = 0.675x Selling Price in Plan 4 = (1 - 0.18) × (1 - 0.18) × x = 0.6724x |
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| 18. |
The marked price of a book is 20% more than the cost price. After the book is sold, the vendor realizes that the he had wrongly raised the cost price by a margin of 25%. If the marked price of the book is Rs. 30, what is the original cost price of the book?1). Rs. 252). Rs. 203). Rs. 454). Rs. 30 |
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Answer» (x + 20/100 × x) = 30 ⇒ x = Rs. 25 Original CP = (25 × 100/125) = Rs. 20 |
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| 19. |
A whole-seller sells half of 200 articles at a profit of 30% and the rest at a profit of 25%. Had all of the articles been sold at a profit of 20%, the total profit would have been Rs. 150 less than earlier profit. The cost price of each article is1). Rs. 102). Rs. 153). Rs. 204). Rs. 30 |
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Answer» Let the cost price of each article be x Total cost price of 200 article = 200x When all of the ARTICLES are sold at a PROFIT of 20%, The profit = 20% of 200x = 40x Further, According to the given INFORMATION, the Whole-seller sells half of 200 articles at a profit of 30% and the rest at a profit of 25% ∴ He sells 100 articles at 30% profit and 100 articles at 25% profit Thus, total profit = (30% of 100X) + (25% of 100x) = 30x + 25x = 55x ? The difference of these two profits is 150 ∴ 55x – 40x = 150 15x = 150 x = 10 Hence the cost price of each article is Rs. 10 |
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| 20. |
Three men started a cafe together. They invested Rs 20000, Rs 16000 and Rs 28000 in the beginning. After 2 months, man B took out Rs 4000 and man C took out Rs 8000. They received a total profit of Rs 8100 from cafe at the end of first year. Calculate the share of man C in profit?1). Rs 30002). Rs 19003). Rs 32004). Rs 2800 |
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Answer» INITIAL investment by man A, B and C are 20000 : 16000 : 28000 Share of man A in 12 MONTHS = 20000 × 12 = 240000 Share of man B in 12 months = 16000 × 2 + 12000 × 10 = 152000 Share of man C in 12 months = 28000 × 2 + 20000 × 10 = 256000 A : B : C = 240000 : 152000 : 256000 = 30 : 19 : 32 ∴ C’s share in profit = 32/(30 + 19 + 32) × 8100 = Rs 3200 |
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| 21. |
1). Rs 12,0002). Rs 14,6403). Rs 21,0004). Rs 30,000 |
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Answer» Let x be the cost PRICE of a refrigerator Given that 20% DISCOUNT the selling price of a refrigerator is Rs.24,000 ⇒ x – 20x/100 = 24,000 ⇒ 80x/100 = 24,000 ⇒ x = Rs. 30,000 If the discount is 30%, we get ∴ Selling price = 30,000 – (30/100 × 30000) = 30,000 – 9,000 = Rs. 21,000 |
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| 22. |
R, S and T started a business by investing Rs. 40000, Rs. 60000 and Rs. _________ respectively. At the end of 4 months, R contributed an additional capital equal to half of T’s initial capital. T left the business at the end of the 4th month while R and S invested for the whole year. S’s share from one year profit of Rs. 9200 was Rs. 3600.1). Rs. 950002). Rs. 550003). Rs. 500004). Rs. 80000 |
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Answer» LET, T’s investment be Rs. x Profit sharing RATIO between R, S and T at the END of 1st year ⇒ [40000 × 4 + (40000 + x/2) × 8] : [60000 × 12] : [x × 4] ⇒ [480000 + 4x] : 720000 : 4x S’s share = 720000/(480000 + 4x + 720000 + 4x) × 9200 = 3600 On solving, we get x = Rs. 80000 |
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| 23. |
1). 20% loss2). 45% gain3). 20% gain4). 30% gain |
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Answer» Let, the cost price of the article = 100A ∴ Marked price of the article = 100A + 100A × 60/100 = 160A ∴ Selling price of the article = 160A – 160A × 25/100 = 120A ∴ OVERALL gain = 120A – 100A = 20A ∴ Gain PERCENTAGE = 20A/100A × 100% = 20% |
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| 24. |
1). 20%2). 23.5%3). 28.5%4). 34.5% |
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Answer» Let the cost PRICE of the goods to be Rs. 100 He had initially marked his goods up by 40%. ∴ After40% mark-up, ⇒ MP = Rs. 100 + 40% of Rs. 100 ⇒ Rs.100 + Rs. 40 = Rs. 140 So,He OFFERS a discount of Rs. 40 on his MP of Rs. 140 ∴ The % discount offered by him = (Discount)/(Marked Price) × 100 ⇒ (40/140) × 100 = 28.5% ∴ The % discount offered by him is 28.5% |
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| 25. |
A dishonest shopkeeper sold onions at Rs. 30/kg which he has bought at Rs. 20/kg. He gave 750g instead of 1 kg. Find his actual profit percentage.1). 10%2). 25%3). 50%4). 100% |
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Answer» Weight of ONIONS bought by customer = 1 kg Actual weight of onions received by customer = 750 g = 0.75 kg PRICE paid by the customer = Rs. 30 Actual price of 0.75 kg = 0.75 × 20 = Rs. 15 ∴ Money earned by the shopkeeper = 30 – 15 = Rs. 15 ∴ PROFIT percentage = (15/15) × 100 = 100% |
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| 26. |
Quantity B: A man bought a TV with 5% discount on marked price of Rs. 60000. He again sold it to his friend with 2% profit on marked price of TV. What profit he had from whole transaction?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: Let the cost price of 10% loss ITEM be Rs.a and cost price of 15% gain item be Rs.b. Selling price of both items = Rs. 450 Loss % = 10% a = (450/0.9) × 100 a = 500 Cost price of item is Rs. 500 which is sold at 10% loss. Gain = 20% b = (450/1.2) × 100 b = 375 Cost price of second item is Rs. 375 which is sold at 20% gain. Total cost price of both items = 500 + 375 = 875 Total selling price including both items = 900 Total profit = 900 – 875 = 25 Quantity B: MARKED price of TV = Rs. 60000 Price of TV after 5% discount = = 60000 – 60000 × 5/100 = 60000 – 3000 = 57000 He sold TV at 2% profit. 2 = [(SP – 60000)/60000] × 100 600 × 2 = SP – 60000 1200 = SP – 60000 SP = 61200 He sold TV at Rs.61200 and he buy TV at Rs. 57000 Total profit amount = 61200 – 57000 = .4200 He got profit of Rs. 4200. From above solution, Relation between Quantity A < Quantity B is established. |
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| 27. |
1). Rs. 5942). Rs. 5993). Rs. 6074). Rs. 499 |
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Answer» As PER the details given in question, Let ASSUME initial marked price = Rs. x Increased in Marked price = 30% Decreased in marked price = 30% At last marked price = Rs. 540 INCREMENT made = x + 30% of x = x + 0.3x = 1.3x DECREMENT made = (x - 30% of x) × 1.3 = (x - 0.3x) × 1.3 = 0.91x [? Decrement had the affect of increment] Final price = Rs. 540.54; Initial price = 0.91x = Rs. 540.54 ⇒ x = 540.54/0.91 = Rs. 594 ∴ Initial price = Rs. 594 |
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| 28. |
After applying successive discounts of 10% and 5% on an article, it was sold at Rs. 513. Find the marked price of the article.1). Rs. 6502). Rs. 6053). Rs. 5604). Rs. 500 |
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Answer» Let the marked price of the ARTICLE be = MP = Rs. x Step 1: CALCULATING SELLING price after first discount First discount = D1 = 10% of MP = 10% of x Selling price = SP1 = MP –Discount SP1 = x –10% of x = $(\frac{9}{{10}})$ x Step 2: Calculating selling price after SECOND discount Second discount = D2 = 5% of SP1 = 5% of $(\frac{9}{{10}})$ x Selling price = SP2 = SP1 –D2 SP2 = $(\frac{9}{{10}})$ x - 5% of $(\frac{9}{{10}})$ x ⇒ SP2 = $(\frac{{95}}{{100}})$ × $(\frac{9}{{10}})$ x ⇒ 513 = $(\frac{{95}}{{100}})$ × $(\frac{9}{{10}})$ x(? Article was finally sold at Rs. 513) ⇒ x = 513 × $(\frac{{100}}{{95}})$ × $(\frac{{10}}{9})$ ⇒ x = Rs. 600 or MP = Rs. 600 |
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| 29. |
The printed price of a book is Rs. 480. A retailer pays Rs. 367.20 for it. He gets successive discounts of 10% and one other rate. His second rate is:1). 15%2). 16%3). 14%4). 13% |
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Answer» GIVEN, printed price of a book is Rs. 480. First DISCOUNT % = 10% SELLING price after 1st discount = 480 – 10% of 480 ⇒ Selling price after 1st discount = Rs. 432 Let the 2nd discount% be d. Selling price after 2nd discount = 432 – d% of 432 Given, final selling price = Rs. 367.20 ⇒ 432 – d% of 432 = 367.2 ⇒ 64.8 = d% of 432 ⇒ d = 15 |
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| 30. |
A shopkeeper purchases 15 packs of four cigars of Jaali brand each pricing Rs. 600. If a shopkeeper sells them illegally at the rate of Rs. 200 per piece. What is the profit percent earned by the shopkeeper?1). 12.5%2). 25%3). 33.33%4). 50% |
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Answer» Total cigars = 15 × 4 = 60 Actual price of cigars = 15 × 600 = Rs. 9,000 Money earned by SELLING all the cigars = 60 × 200 = Rs. 12,000 Profit earned = 12000 – 9000 = Rs. 3000 Profit % earned = (3000/9000) × 100 = 33.33% |
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| 31. |
1). Rs. 8402). Rs. 10803). Rs. 10004). Rs. 1200 |
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Answer» COST price of Book = Rs. 800 Profit earned = 5% We KNOW, Selling Price = Cost Price × (1 + (Profit Percentage)/100) ⇒ Selling price = $(800 \times \;\left( {1 + \;\frac{5}{{100}}} \RIGHT))$ ⇒ Selling price = 800 × 1.05 = 840 Suppose the marked price of book is M. We know, Selling Price = Marked Price × (1 – (Discount Percentage)/100) So, $(840 = M \times \;\left( {1 - \;\frac{{30}}{{100}}} \right))$ ⇒ 840 = 0.7 M ⇒ M = 840/0.7 = 1200 ∴ Marked price of book is Rs. 1200. |
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| 32. |
A dishonest shopkeeper professes to sell his goods at the cost price but use faulty measure. His 1 kg weight measures 950 gms only. Find his gain percent.1). \(7\frac{3}{{19}}\% \)2). \(5\frac{7}{{19}}\%\)3). \(5\frac{5}{{19}}\%\)4). \(\;4\frac{5}{{19}}\%\) |
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Answer» ⇒ Here, true measure = 1000 gms ⇒ False measure = 950 gms Since the shopkeeper SELLS the goods at cost price ⇒ x = 0 ⇒ overall gain % is GIVEN by, ⇒ True measure/ Faulty measure = (100 + G)/ (100 + x) ⇒ 1000/ 950 = (1000 × g)/ 950 ⇒ 100 + g = (1000 × 100)/ 950 $( \Rightarrow {\rm{g}} = 5\frac{5}{{19}}\%)$ |
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| 33. |
Rakesh thinks to make 48% profit after allowing a discount of 60% on the marked price, cost price of an article has to be increased by how much percentage?1). 70%2). 170%3). 270%4). 370% |
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Answer» Let the cost price of an ARTICLE be RS. x. For 48% profit, sell price = cost price (1 + profit %) = Rs. x (1 + 0.48) = Rs. 1.48x But this sell price is obtained after 60% discount on Marked Price. Sell Price = Marked Price (1 − Discount %) ⇒ 1.48x = Marked Price (1 − 0.60) ⇒ Marked Price = $(\frac{{1.48x}}{{0.4}}\; = \;3.7x)$ ∴ The object should be marked at 270% HIGHER price. |
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| 34. |
A man bought a horse and a pony for Rs. 2500. He sold the pony at a profit of 15% and the horse at a profit of 25%. If his total profit was Rs. 500, what is the cost price of the horse?1). Rs. 19502). Rs. 18003). Rs. 21004). Rs. 2000 |
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Answer» Let the cost price of pony be RS. x ∴ Cost price of the horse = Rs. (2500 – x) Profit on pony = 15% ⇒ GAIN = (15 × x)/100 = Rs. 3x/20 Profit on horse = 25% ∴ Profit = [(2500 – x) × 25]/100 = Rs. (2500 – x)/4 Total profit = Rs. 500 ∴ 3x/20 + (2500 – x)/4 = 500 ⇒ 3x + [5 × (2500 – x)] = 500 × 20 ⇒ 3x + 12500 – 5x = 10000 ⇒ 2x = 2500 ⇒ x = 1250 ∴ Cost price of the horse is = 2500 - 1250 = Rs. 1250 |
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| 35. |
1). Rs. 654.42). Rs. 458.43). Rs. 565.64). Rs. 640.5 |
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Answer» LET the cost price at which A bought be x. A sold it to B with a loss of 15% ∴ SP1 = 85x/100 B sold it to C at a no PROFIT or loss ∴ SP2 = SP1 = 408 408 = 85x/100 ∴ x = Rs. 480 To get a profit of 36% A should sell at a price = (136/100) × 480 = Rs. 652.8 |
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| 36. |
Quantity B: 100001). Quantity A > Quantity B2). Quantity A ≥ Quantity B3). Quantity B > Quantity A4). Quantity B ≥ Quantity A |
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Answer» QUANTITY A:$ LET the purchase PRICE of phone = Rs. x ⇒ CURRENT price = x × 80% × 80% ⇒ 12000/(0.8 × 0.8) = x ⇒ x = Rs. 18,750 Quantity B: 10000 ∴ Quantity A > Quantity B |
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| 37. |
A shopkeeper sold an article at a gain of 20%. If he had paid Rs. 225 less for it and sold it at the same price he would have made a gain of 50%. Find the cost price.1). Rs. 17502). Rs. 9753). Rs. 12504). Rs. 1125 |
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Answer» Let the C.P. of ARTICLE be Rs. x. When the article is sold at 20% gain, S.P. = x + (20% of x) = 1.2x Had he bought the product for Rs.225 less, the cost price = x – 225 ∴ when he sells the article at the same price as before, % gain $(= \frac{{S.P. - C.P.}}{{C.P.}} \times 100)$ ⇒ 50 $(= \frac{{1.2x - \left( {x - 225} \right)}}{{x - 225}} \times 100)$ ⇒ 50 (x – 225) = 100 (0.2x + 225) ⇒ 50X – 11250 = 20x + 22500 ⇒ 30x = 33750 ⇒ x = 33750/30 = 1125 The C.P. of the article is Rs. 1125 |
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| 38. |
If a shopkeeper increases the marked price by 25% and agrees to give two successive discount of 10% each. How much percent does he gain by his dishonest dealing?1). 5%2). 10%3). 1.25%4). 15% |
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Answer» Let the original PRICE be x New price of SOAP = x + (25/100) × x = 125x/100 = 1.25x Price after first discount = (90/100) × (125x/100) = 1.125x Price PAID by PURCHASER = (90/100) × 1.125x = 1.0125x Profit of shopkeeper = 1.0125x – x = 0.0125x ∴ Profit% = (0.0125x)/x × 100 = 1.25% |
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| 39. |
A person buys a car marked at Rs. 300000 at successive discounts of 10% and 7.5%. If he sells the car at Rs. 254745, what is the profit or loss percent that he makes?1). 2% profit2). 2% loss3). 5% loss4). 5% profit |
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Answer» Marked Price of Car = Rs. 300000 After SUCCESSIVE discounts of 10% and 7.5%, SELL Price = Rs. 300000 × (0.9) × 0.925 = Rs. 249750 Cost price for the person = Rs. 249750 ∴ Sell price for the person = Rs. 254745 Profit = Rs. (254745 - 249750) = Rs. 4995 $(\therefore {\RM{Profit\% }} = {\rm{}}\frac{{4995}}{{249750}} \TIMES 100 = 2\% )$ |
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| 40. |
A sold a pen to B at Rs. 60 profit. ‘B’ increased its marked price by 50% and then sold it to C at a discount at 25%. Profit earned by ‘B’ is Rs. 10 more than A. Find A’s cost price?1). 2502). 5003). 7504). 1000 |
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Answer» Given, PROFIT after A sold pen = Rs. 60 Let the A's cost price of a pen be Rs. a. Purchased price of B = selling price of B = Rs. (60 + a) Given, B increased its MARKED price by 50% New marked price of pen = (60 + a) + (60 + a) × 50/100 = 60 + a + 30 + a/2 = 90 + 3a/2 Given, B sold pen to C at 25% discount. Selling price of B = (90 + 3a/2) - (90 + 3a/2) × 25/100 = (360 + 6a - 90 - 3a/2)/4 = (270 + 9A/2)/4 B had Rs. 10 more profit than A. Profit amount for B = 60 + 10 = 70 Then, ⇒ 70 = (270 + 9a/2)/4 - (60 + a) ⇒ 280 = 270 + 9a/2 - 240 - 4a ⇒ 560 = 540 + 9a - 480 - 8a ⇒ a = 500 ∴ A's cost price of a pen is Rs. 500. |
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| 41. |
A man sells an article at 14 % profit. Had he bought it at 14 % less and sold it for Rs. 1424 less, he would have gained 16%. Find the cost price.1). Rs. 105002). Rs. 100003). Rs. 95004). Rs. 5000 |
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Answer» Let the Cost price be Rs. x ? the article is sold at 14% PROFIT, Selling price = x + (14% of x) = 1.14x Now, in the second case, the article was bought at 14% lesser value than the previous value ∴ Cost price in second case = x – (14% of x) = 0.86x In the second case, the article was sold at a price Rs. 1424 LESS than the previous selling price. ∴ Selling price in second case = 1.14x – 1424 Now, Gain in the second case = (1.14x – 1424) – 0.86x ∴ % gain $(= \frac{{\LEFT( {1.14x - 1424} \right) - 0.86x}}{{0.86x}} \times 100)$ ⇒ $(16\; = \frac{{\left( {1.14x - 1424} \right) - 0.86x}}{{0.86x}} \times 100)$ ⇒ 16 × 0.86x = 100 × (0.28X – 1424) ⇒ 13.76x = 28x – 142400 ⇒ 14.24x = 142400 ⇒ x = 10000 ∴ Cost price of the article is Rs. 10000. |
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| 42. |
Arun, Kamal and Vinay invested Rs.8000, Rs.4000 and Rs.8000 respectively in a business. Arun left after six months. If after eight months, there was a gain of Rs.4005, then what will be the share of Kamal?1). Rs.17802). Rs.13353). Rs.16024). Rs.890 |
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Answer» SAY P% is the rate of profit per month. All three INVESTED for 6 months and after that, only Kamal and Vinay invested for remaining two months. ⇒ Profit share of Arun = 6 × (P% of 8000) = 480P Profit share of Kamal = 8 × (P% of 4000) = 320P Profit share of Vinay = 8 × (P% of 8000) = 640P Total profit by all three in 8 months = 480P + 320P + 640P = 1440P Given total profit = Rs.4005 ⇒ 1440P = 4005 ⇒ P = 4005/1440 Profit share of Kamal = 320P = 320 × (4005/1440) = 4005/4.5 = Rs.890 |
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| 43. |
The cost price of a Hard disk is Rs 3200 and the selling price is Rs 3300, find the percentage profit?1). 3.5%2). 3.125%3). 3.25%4). 3.75% |
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Answer» We know that, % Profit = (S.P. - C.P)/(C.P.) × 100 ⇒ Profit% = (3300 – 3200/3200 × 100 ⇒ Profit% = 100/3200 × 100 = 3.125% ∴ Profit earned on HARD DISK is 3.125% |
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| 44. |
A fruit vendor sells his fruits at 21% profit. If he had bought it for 9% less and sold it for Rs. 29 less, he would have gained 25%. The cost price of fruit is:1). Rs. 3602). Rs. 3203). Rs. 4004). Rs. 480 |
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Answer» Let the cost price of fruit be Rs. X. ∴ Sell Price = Rs. 1.21x If he had bought it at 9% LESS price, Cost Price = 0.91x If he would have sold at Rs. 29 less, Sell Price = Rs. (1.21x − 29) Profit = Sell Price − Cost Price = Rs. (0.3x − 29) $({\rm{Profit\% \;}} = {\rm{\;}}\frac{{Profit}}{{Cost\;Price}}\; \times \;100)$ ⇒ $(25{\rm{\;}} = {\rm{\;}}\frac{{0.3x\; - \;29}}{{0.91x}}\; \times \;100)$ ⇒ 0.25 × 0.91x = 0.3x - 29 ⇒ 0.3x − 0.2275x = 29 ∴ x = 400 The cost price of fruit is Rs. 400. |
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| 45. |
Quantity B: A shopkeeper makes changes in weight balance that is weight balance counts 940g instead of 1000 kg. What is profit percentage he had?1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: Let the Cost price of GOODS be Rs.100. Given, A shopkeeper sets his goods price at 30% above the cost price Then it’s marked price set by shopkeeper is Rs.130. After this he is OFFERING 10% DISCOUNT for cashless payments, SELLING price after discount is = = 130 – 130 × 10/100 = 130 – 13 = 117 Selling price of goods after discount = Rs.117 Profit percentage he had in this transaction = = ((SP – CP)/CP) × 100 = ((117 – 100)/100) × 100 = 17 Profit percentage he had is 17%. Quantity B: Given, weight balance counts 940g instead of 1000kg Let for 1 kg weight cost price is Rs.100 That is due to faulty weight balance, He sells goods of Rs.94 at price of goods 1kg. Gain he had = 100 – 94 = 6 Percentage profit he had = = (6/94) × 100 = 6.38% Due to faulty weight balance shopkeeper had 6.38% profit. From above solution, Relation between Quantity A > Quantity B is established. |
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| 46. |
1). Rs. 10,5002). Rs. 11,6003). Rs. 13,8004). Rs. 14,200 |
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Answer» Let the COST price at which A BOUGHT be x. A sold it to B with a loss of 18% ∴ SP1 = 82x/100 B sold it to C at a profit of 30% ∴ SP2 = 130 SP1/100 = 12792 12792 = (82x/100) × (130/100) ∴ x = Rs. 12,000 To get a profit of 15% A should sell at a price = (115/100) × 12000 = Rs. 13800 |
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| 47. |
The marked price of a pair of shoes is Rs. 1300. It is sold at a successive discount series of 30%, 20% and 10%. Due to the discount, the seller faces a loss of 20%. What is the cost price of pair of shoes (in Rs.)?1). 8002). 8103). 8194). 867 |
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Answer» Loss is 20%. We know, Selling Price = Cost Price × (1 – (Loss %)/100) ⇒ Selling price = T × (1 – 20/100) = 0.8T Also, In case of successive discounts, Selling Price = MARKED Price × (1 – Discount1/100) × (1 – Discount2/100) ……. ⇒ 0.8T = 1300 × (1 – 30/100) × (1 – 20/100) × (1 – 10/100) = 1300 × 0.7 × 0.8 × 0.9 = 655.2 ⇒ T = 655.2/0.8 = 819 ∴ Cost price of pair of shoes is Rs. 819. |
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| 48. |
Quantity B: Ram has 30 storybooks, out of which he sells some at 2% profit and rest other at 6% profit. He gains 4% in the whole process. What is the profit amount collected from storybooks sold at 6% profit if Cost price of a storybooks is Rs. 120.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: The cost price of products = Rs.300 GAIN % = 20% Selling price = Rs.360 Let marked price be Rs.a. Discount is 10% on marked price. 90% of a = 360 a = (360 × 100)/90 a = 3600/9 a = 400 The marked price of product is Rs.400 Quantity B: Ram has 30 storybooks. Some sold at 2% profit and some at 6%. In whole transaction he had 4% profit. The cost price of a storybook is Rs.120 Gain % = 4% Cost price of 30 storybooks = 30 × 120 = 3600 Gain % = [(SP – CP)/ CP] × 100 All Gain percentage are given, (Number of books sold at 2%)/(number of books sold at 6%) = (6 – 4)/(4 – 2) = 2/2 = 1/1 Number of books sold at 2% = number of books sold at 6% = 30/2 = 15 Cost price of 15 books = 15 × 120 = 1800 Selling price of 15 books at 6% = = [(100 + 6)/100] × 1800 = 1908 Profit amount of 15 books with 6% gain = = 1908 – 1800 = 108 From above solution, Relation between Quantity A > Quantity B is established. |
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| 49. |
A merchant purchases a wrist watch for Rs. 450 and fixes its list price in such a way that after allowing a discount of 10%, he earns a profit of 20%. Then the list price of the watch is ________.1). Rs. 6502). Rs. 7003). Rs. 5504). Rs. 600 |
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Answer» LET the LIST price of a watch be Rs. m. Cost price of a watch = Rs. 450 Discount percentage = 10% Selling price of a watch = m – m × 10/100 = 9m/10 Profit percentage = 20% Profit percentage = [(S.P – C.P)/C.P] × 100 ⇒ 20 = [(9m/10 – 450)/450] × 100 ⇒ 90 = 9m/10 – 450 ⇒ 9m/10 = 540 ⇒ m = 600 ∴ List price of a watch is Rs. 600. |
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| 50. |
Airtel and Nokia entered into a partnership 7 months ago. The ratio of revenues claimed by Airtel to Nokia is 5 ∶ 7. If Nokia had started the business 12 months ago with Rs. 735 thousand crores, what is the amount contributed by Airtel?1). Rs. 900 thousand crores2). Rs. 525 thousand crores3). Rs. 749 thousand crores4). Rs. 1050 thousand crores |
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Answer» Let Airtel had invested Rs. x THOUSAND crores for seven months. Ratio of time invested by Nokia to Airtel = 12 ? 7. Ratio of MONEY invested by Nokia to Airtel = 735 ? x Ratio of REVENUES = $(\frac{{12 \TIMES 735}}{{7 \times x}} = \frac{7}{5})$ $(\Rightarrow x = \frac{{12 \times 735 \times 5}}{{7 \times 7}} = 12 \times 15 \times 5 = 900)$ ∴ AMOUNT contributed by Airtel = Rs. 900 thousand crores |
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