InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
1). 84,0002). 864,0003). 672,0004). 708,000 |
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Answer» Let investment made by Raj per month = Rs. X Ratio of their PROFITS will be the same as ratio of their total INVESTMENTS, $(\Rightarrow \frac{{72,000\; \times 12}}{{x \times 8}} = \frac{9}{7})$ ⇒ 6048000 = 72x ⇒ x = 6048000/72 ⇒ x = 84,000 |
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| 52. |
Rita buys a toaster at some price. However, she finds it defective and sells to Ram at 20% loss. Ram repairs it and sells at a profit of 40% to Rekha. If Rekha buys it for Rs. 5600, how much loss did Rita suffer?1). Rs. 12002). Rs. 11203). Rs. 14004). Rs. 1000 |
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Answer» Ram SOLD the toaster at 40% profit. Using the FORMULA, $({\rm{CP\;}} = {\rm{}}\frac{{{\rm{SP}}}}{{1{\rm{}} + {\rm{profit\% }}}})$ Where, CP = cost price SP = Selling Price Putting SP = Rs. 5600 and profit percent = 40%, we GET CP = Rs. 4000. ∴ Ram has bought it for Rs. 4000. Rita had sold it for 20% loss. Putting SP = 4000 and loss = 20%. C.P = Rs. 5000 ∴ Rita had bought it for Rs. 5000. ∴ Loss suffered by Rita = Rs. (5000 − 4000) = Rs. 1000 |
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| 53. |
A Shopkeeper promises to sell the cooking oil at x% profit, but he cheats while selling the oil by giving 20% less by weight. Find the value of x if he actually gains 35% profit.1). 122). 103). 84). 6 |
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Answer» Suppose the cost PRICE of 100L oil is Rs.100 Since he promises to sell the oil at x% profit, he promises that he is selling 100L oil for Rs. (100 + x) But he cheats while selling the oil by giving 20% less by weight ⇒ ACTUALLY he SELLS (100 × 0.80) = 80L oil for Rs. (100 + x) ⇒ Selling price of 100L oil = Rs. [(100 + x)/80] × 100 Since his actual profit is 35%, he will be getting Rs. 135 for 100L oil ∴ [(100 + x)/80] × 100 = 135 ⇒ 100 + x = 108 ⇒ x = 8 |
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| 54. |
A dishonest shopkeeper marks-up his goods by 50% and gives a discount of 20%. Besides it, being a defraud, he weighs 20% less amount while selling his goods. What is the net profit of the shopkeeper?1). 25%2). 35%3). 40%4). 50% |
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Answer» Let original cost price of the GOODS be Rs. 100 He marked his goods at 50% above the cost price, ∴ Marked price of the goods = Rs. 150 He gives a discount of 20% on marked price, ∴ Selling Price = 150 × (80/100) = Rs. 120 ? He weighs 20% less ∴ Actual cost price = 100 - (20% of 100) = Rs. 80 Profit = SP - CP = 120 - 80 = Rs. 40 ∴ Profit percentage = $(\FRAC{{80{\rm{\;}} - {\rm{\;}}40}}{{80}} \times 100 = 50\%)$ |
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| 55. |
A dishonest shopkeeper makes cheating of 10% at the time of buying and 10% at the time of selling the goods. Find profit percent.1). 0%2). 10%3). 20%4). 21% |
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Answer» Let cost PRICE of 1 GM goods = RS. 1 Letthe shopkeeper purchases 100 gm goods. TOTAL cost price = Rs. 100 Due to cheating he actually gets = 100 + (10/100) × 100 = 110 gm goods. Due to cheating at the TIME of selling the goods, he sells = 110 + 110× (10/100) = 121 gm goods Total selling price = Rs. 121 Required profit percentage = (121 – 100)/100 × 100 = 21% |
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| 56. |
Golu and Risu invested in the ratio 3 : 2 in a business. If 5% of the total profit goes to charity and Golu’s share is Rs. 855. Find the total profit.1). Rs. 18002). Rs. 13003). Rs. 15004). Rs. 2700 |
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Answer» ⇒ Suppose the total PROFIT is Rs. 100 ⇒ Then Rs. 5 goes to charity. ⇒ Now, Rs. 95 is divided in the ratio 3 : 2 ∴ Golu’s share = 95/(3 + 2) × 3 = Rs. 57 ∴ Actual total profit = Rs. 855(100/57) = Rs. 1500 |
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| 57. |
An article was purchased for Rs. 8,760. Its price was marked up by 25%. It was sold at a discount of 10% on the marked up price. What was the profit percent on the cost price?1). 12.52). 7.53). 54). 15 |
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Answer» Cost price of the ARTICLE = Rs. 8760 It is marked up by 25% ∴ marked price of the article, ⇒ 8760 + [8760 × (25/100)] = Rs. 10950 Discount given = 10% ∴ DISCOUNTED price = 10950 - 10950 × (10/100) = 9855 ∴ Profit = 9855 - 8760 = Rs. 1095 ∴ Profit percent = (1095/8760) × 100% = 12.5% |
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| 58. |
The cost per kilogram of pomegranate is Rs. 15 and that of pineapple is Rs. 10. Raghu purchased 60 kilograms of pomegranate and pineapple for Rs. 700. The quantity of pomegranate purchased is ______ kilograms.1). 25 kg2). 20 kg3). 22 kg4). 28 kg |
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Answer» Let the quantity of POMEGRANATE bought be x kg and that of PINEAPPLE be (60 - x) kg. ∴ According to the question, ⇒ 15x + (60 - x)10 = 700 ⇒ 15x + 600 – 10x = 700 ⇒ 5x + 600 = 700 ⇒ 5x = 100 ∴ x = 20 |
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| 59. |
A and B started a business in partnership with the investment of Rs. 27000 and Rs. 36000 respectively. After 4-months A withdrew Rs. 5000 and B added Rs. 6000 more and C joined with Rs. 35000 If after one year they get a total profit of Rs. 130500, then find the profit share of C.1). Rs. 360002). Rs. 320003). Rs. 350004). Rs. 38000 |
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Answer» Share of each member in profit = Amount × TIME invested Total share of A in profit = 27000 × 4 + 22000 × 8 Total share of B in profit = 36000 × 4 + 42000 × 8 Total share of C in profit = 35000 × 8 Ratio of profit = 71 : 120 : 70 Share of C = (70/261) × 130500 = Rs. 35,000 |
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| 60. |
Rakesh, Ramesh and Suresh went to a market to purchase watches whose costs were same. But each watch was available with two successive discounts. Rakesh availed two successive discounts of 20% and 5%. Ramesh availed two successive discounts of 15% and 10% while Suresh availed two successive discounts of 12% and 13%. Who gets the maximum possible discount?1). Rakesh2). Ramesh3). Suresh4). All of the above |
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Answer» Let the marked price of WATCHES is Rs. 100 For Rakesh, ⇒ FIRST discount = 100 – (20% of 100) = 80 ⇒ Second discount = 80 – (5% of 80) = 80 – {(5/100) × 80} = 76 ⇒ Total discount = 100 – 76 = 24 For Ramesh, ⇒ First discount = 100 – (15% of 100) = 85 ⇒ Second discount = 85 – (10% of 85) = 85 – 8.5 = 76.5 ⇒ Total discount = 100 – 76.5 = 23.5 For Suresh, ⇒ First discount = 100 – (12% of 100) = 88 ⇒ Second discount = 88 – (13% of 88) = 88 – {(13/100) × 88} = 76.56 ⇒ Total discount = 100 – 76.56 = 23.44 ∴ Rakesh gets the maximum discount Alternatively:- We have a formula of two successive discounts, for two successive discounts a and b, ⇒ Total discount = a + b – (ab/100) ⇒ Rakesh’s discount = 20 + 5 – {(20)(5)/100} = 25 – 1 = 24 ⇒ Ramesh’s discount = 15 + 10 – {(15)(10)/100} = 25 – 1.5 = 23.5 ⇒ Suresh’s discount = 12 + 13 – {(12)(13)/100} = 25 – 1.56 = 23.44 ∴ Rakesh gets the maximum discount |
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