1. a - [2b - {3a - (2b - 3c)}] – InterviewSolution

1.	1. a - [2b - {3a - (2b - 3c)}]
Answer» Answer: Step-by-step explanation: We FIRST remove the INNERMOST GROUPING symbol ( ), then { } and then [ ] We have, a–[2b–{3a–(2b−3c)}] =a–[2b–{3a–2b+3c}] =a–[2b–3a+2b–3c] =a–2b+3a–2b+3c Rearranging and collecting the like TERMS, we GET: =a–3a–2b–2b+3c =4a–4b+3c

1. a - [2b - {3a - (2b - 3c)}]

Answer»

Answer:

Step-by-step explanation:

We FIRST remove the INNERMOST GROUPING symbol ( ), then { } and then [ ]

We have,

a–[2b–{3a–(2b−3c)}]

=a–[2b–{3a–2b+3c}]

=a–[2b–3a+2b–3c]

=a–2b+3a–2b+3c

Rearranging and collecting the like TERMS, we GET:

=a–3a–2b–2b+3c

=4a–4b+3c