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1 A current passes through a long solenoid. Number of turns in the solenoid is 3000 per 0.6m. Find the flux density at a point on its axis. DATA: i = 1A, n=(3000)/(0.6)=5000 mu_@=4pixx10^(-7) (Wb)//A To find:B=?

Answer»

SOLUTION :MAGNETIC field B on the axis of the SOLENOID:
`B=mu_@ni`
`(4xxpixx10^(-7)xx5000xx2)/1= 2pixx10^(-3)T`.


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