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1. A line AB is of length 6 cm. Another line CD is of length 15 cm. What fraction is :(i) the length of AB to that of CD ?1(ii) the length of AB to that of of CD ?231 /(iii)of CD to that of AB ?5​

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Answer:

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Explanation:

Answer

It is given that

Length of AB=6 CM

Length of CD=15cm

(i) The length of AB to that of CD

=6/15

=2/5

(ii) 1/2 the length of AB to that of 1/3 of CD

1/2 of AB = 1/2×6 =3cm

1/3 of CD = 1/3×15 =5cm

So 1/2 the length of AB to that of 1/3 of CD = 3/5

(iii) 1/5 of CD to that of AB

1/5 of CD = 1/5×15 = 3 cm

1/5 of CD to that of AB = 3/6 = 1/2 cm



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