1. A particle moves along a straight line Ox, at a time t (in seconds)

1.	1. A particle moves along a straight line Ox, at a time t (in seconds) the distance x (in meters) of the particlefrom O is given by x 40+ 12t-t3(A) 24 m(B) 40 m(C) 56 m(D) 16 m
Answer» We have equation x= 40+12t-t^3. So initially take t=0 => x=40m. Now differtiate the equation with respect to time(t) which is equal to velocity (v) {v=dx/dt} now put v=0 as the particle is stopping you will get value of t. Put this value in "40+12t-t^3" and you will get final distance.on Subtracting the initial distance from this final distance we'll get x=16m.

1. A particle moves along a straight line Ox, at a time t (in seconds) the distance x (in meters) of the particlefrom O is given by x 40+ 12t-t3(A) 24 m(B) 40 m(C) 56 m(D) 16 m

Answer»

We have equation x= 40+12t-t^3. So initially take t=0 => x=40m.

Now differtiate the equation with respect to time(t) which is equal to velocity (v) {v=dx/dt} now put v=0 as the particle is stopping you will get value of t. Put this value in "40+12t-t^3" and you will get final distance.on Subtracting the initial distance from this final distance we'll get x=16m.

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1. A particle moves along a straight line Ox, at a time t (in seconds) the distance x (in meters) of the particlefrom O is given by x 40+ 12t-t3(A) 24 m(B) 40 m(C) 56 m(D) 16 m

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