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1) AB and CB are two chords of circle. Prove that BO bisects angle 8. (3) |
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Answer» -step explanation:Given: In the figure, AB = CB and O is the CENTRE of the circle. To Prove: BO bisects ∠ABC. Construction: Join OA and OC.Proof : In ∆OAB and ∆OCB, OA = OC [RADII of the same circle] AB = CB [Given] OB = OB [COMMON] ∴ ∆OAB ≅ ∆OCB [By SSS] ∴ ∠ABO = ∠CBO [By CPCTC] ⇒ BO bisects ∠ABC. |
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