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1. An iron sphere of mass 10 kg is dropped from a height of 80 cm, ifCalculate the momentum transferred to the ground by the body-10 m / s",0

Answer»

final velocity of the iron sphere just before ground is v² = (2)*(10)*(0.80) = 16v = √16 = 4m/s

now... momentum transfer to the ground is ∆m = m(v1-v2) = 10(4) = 40kg-m/s



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