1 at 581k.Calculate the fraction of molecules of reactants having ener

1.	1 at 581k.Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?
Answer» In the given case: Ea = 209.5 KJ mol - 1 = 209500 J mol - 1 T = 581 K R = 8.314 JK - 1 mol - 1 Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as

1 at 581k.Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

Answer»

In the given case:

Ea = 209.5 KJ mol - 1 = 209500 J mol - 1

T = 581 K

R = 8.314 JK - 1 mol - 1

Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as