1 c.c of 0.1 N HCl is added to 1 litre solution ofsodium chloride. The pH of the resulting solution willbe(2) 0(4) 4(3) 10

1 c.c of 0.1 N HCl is added to 1 litre solution ofsodium chloride. Th

1.	1 c.c of 0.1 N HCl is added to 1 litre solution ofsodium chloride. The pH of the resulting solution willbe(2) 0(4) 4(3) 10
Answer» <p>The pH of the solution is determined from the concentration of H+. The concentration of H+will be determined from HCl.pH = -log[H+]The concentration of H+ion is expressed in mol L-1or M.First we need to find the number of moles of 0.1 NHClNormality =(numberofmoles/Volumeofsolution(inliters))×numberofdisplacableH+inacidVolume of HCl added = 1 cm3Number of displacable H+in HCl = 11 cm3= 10-3L0.1 = n/10-3 (n is the number of moles of HCl)n = 10-4molesFinal volume of the solution on addition of HCl in 1 L of NaCl = 10-3+ 1 = 1.001 LNormailty of HCl = 10-4/1.001 = 10-4NNormality is equivalent to Molrity for HCl as the number of displacable H+is one.pH = -log[10-4]pH = 4Therefore, the pH of the resulting solution will be 4.</p>