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1) Charli is counting in steps of5/6 My sequence cannot includea mixed number containing 1/2Charli is incorrect.Prove it by writing a sequence that includes a mixed number containing 1/2 |
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Answer» (A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2AB = 3B(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab |
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