InterviewSolution
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InterviewSolution
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`1 cm^(3)` of water at its boiling point absorbs `540 cal` of heat to become steam with a volume of `1671 cm^(3)`. If the atmospheic pressure is `1.013 xx 10^(5) N//m^(2)` and the mechanical equivalent of heat `= 4.19 J//cal`, the energy spent in this process in overcoming intermolecular forces isA. `540 cal`B. `40 cal`C. `500 cal`D. Zero |
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Answer» Correct Answer - C c. Energy spent in overcoming inter-molecular forecs. `Delta U = Delta Q - Delta W` `Delta Q - P(V_(2) - V_(1))` `= 540 - (1.013 xx 10^(5) (1671 - 1) xx 10^(-6))/(4.2)` `implies 500 cal` |
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