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1. Find the area of a triangle having sides of length 15 cm, 28 cm and 4lom Also find the length of cel altitude drown from opposite Wester tothe side of length 28 cm​

Answer»

-step explanation:Perimeter of triangle is 40 (cm). Area of triangle is 60(cm^{2})(cm 2 ) . Altitude on side 17 cm is 7.059 (cm).Step-by-step explanation:1. Side of triangle is 8 cm, 15 cm and 17 cm.So Perimeter of triangle = Sum of side of trianglePerimeter of triangle= 8+15+ 17=40 (cm)2. If we SEE side of triangle8^{2}+15^{2}=17^{2}8 2 +15 2 =17 2 64+225=17^{2}64+225=17 2 289=17^{2}289=17 2 17^{2}=17^{2}17 2 =17 2 Means it SATISFIED Pythagoras ruleIt must be a RIGHT angle triangle, and right angle opposite to side longest side 17 (cm).3. Base =15 cm Perpendicular= 8 cm Hypotenuse =17 CM4. So area of triangle =\frac{1}{2}\times base\times perpendicular=\frac{1}{2}\times 15\times 8=60(cm^{2})= 21 ×base×perpendicular= 21 ×15×8=60(cm 2 )5.Area of triangle=\frac{1}{2}\times base\times Perpendicular=\frac{1}{2}\times Hypotenuse\times altitude= 21 ×base×Perpendicular= 21 ×Hypotenuse×altitude We can also write \frac{1}{2}\times Hypotenuse\times altitude= 21 ×Hypotenuse×altitude= Area of triangle \frac{1}{2}\times 17\times altitude= 60 21 ×17×altitude=60 On SOLVING Altitude =7.059 (cm)



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