1. Find the area of the shaded region. Given ABCD is a square of side

1.	1. Find the area of the shaded region. Given ABCD is a square of side 28cm. BPC is a seminircle & APD is a triangle?
Answer» Answer Is 280 cm² Step-by-step EXPLANATION: Given:- Side OF Square = 28 cm. BPC Is A Semicircle With Radius 14 cm ( 28/2) APD Is A Triangles So:- there is AC And BD are DIAGONALS Od Square So The height of Triangle APD is 14 CM Areas:- Area Of Square = (Side×Side) 28×28 = 784 cm² Area Of Semicircle = (πR²/2) (22/7 × 14 × 14)/2 = 308 cm² Area Of Triangle = (1/2 × BASE × Height) 1/2 × 28 × 14 = 196 cm² Area Of Shaded Region = (Area Of Square) - [(Area Of Semicircle) + (Area Of Triangle)] = 784 cm² - (308 cm² + 196 cm²) = 784 cm² - 504 cm² = 280 cm² Hope it will help u

1. Find the area of the shaded region. Given ABCD is a square of side 28cm. BPC is a seminircle & APD is a triangle?

Answer»

Answer Is 280 cm²

Step-by-step EXPLANATION:

Given:-

Side OF Square = 28 cm.

BPC Is A Semicircle With Radius 14 cm ( 28/2)

APD Is A Triangles

So:-

there is AC And BD are DIAGONALS Od Square

So The height of Triangle APD is 14 CM

Areas:-

Area Of Square =

(Side×Side) 28×28 = 784 cm²

Area Of Semicircle =

(πR²/2) (22/7 × 14 × 14)/2 = 308 cm²

Area Of Triangle =

(1/2 × BASE × Height) 1/2 × 28 × 14 = 196 cm²

Area Of Shaded Region =

(Area Of Square) - [(Area Of Semicircle) + (Area Of Triangle)]

= 784 cm² - (308 cm² + 196 cm²)

= 784 cm² - 504 cm²

= 280 cm²