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1: Find two solutions for each of the following equations:(i) 4x + 3y = 12(ii) 2x + 5y = 0(iii) 3y + 4 = 0​

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Answer:

Step-by-step explanation:

HELLO DEAR,

(1)..LET,X=0

WE GET,

3Y=12

Y=4

The solution is(0,4)

and we take,Y=0

WE GET,

4X=12

X=3

ANOTHER SOLUTION IS (3,0)

(2).LET,X=0

WE GET,

5Y=0

Y=0

SOLUTION IS (0,0)

AND

TAKE Y=0

WE GET,

2X=0

X=0

{noth solution is same hence we not get DIFFERENT Solution}

(3).LET X=0

0.X+3Y+4=0

3Y=-4

Y=-4/3

SOLUTION IS (0,-4/3)

and

we take,

Y=1

WE GET,

3Y=-4

Y=-4/3

SOLUTION IS (1,-4/3)

solutions are same

IN fact (K,-4/3)

for all REAL values of x

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