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1). \(\frac{5}{{54}}\)2). \(\frac{7}{{54}}\)3). \(\frac{4}{{45}}\)4). \(\frac{2}{{18}}\) |
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Answer» Let a and b be two numbers. We know (H.C.F) × (L.C.M) = Product of two numbers Putting H.C.F and L.C.M. as 9 and 54 respectively we get a × b = 9 × 54 Also, a + b = 45 Solving the two EQUATIONS by SUBSTITUTING the value of a from above equation in a × b = 9 × 54 we get a and b as 18 and 27. So, $(\FRAC{1}{a} + \frac{1}{b} = \frac{1}{{18}} + \frac{1}{{27}})$ i.e. 5/54 |
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