1.

1). \(\frac{5}{{54}}\)2). \(\frac{7}{{54}}\)3). \(\frac{4}{{45}}\)4). \(\frac{2}{{18}}\)

Answer»

Let a and b be two numbers.

We know (H.C.F) × (L.C.M) = Product of two numbers

Putting H.C.F and L.C.M. as 9 and 54 respectively we get a × b = 9 × 54

Also, a + b = 45

Solving the two EQUATIONS by SUBSTITUTING the value of a from above equation in a × b = 9 × 54 we get a and b as 18 and 27.

So, $(\FRAC{1}{a} + \frac{1}{b} = \frac{1}{{18}} + \frac{1}{{27}})$

i.e. 5/54



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