1 g mixture of glucose and urea present in 259 mL aqueous solution shows the osmotic pressure of 0.74 atm at 27^(@)C. Assuming solution to be dilute, select the correct statements:

1 g mixture of glucose and urea present in 259 mL aqueous solution sho

1.	1 g mixture of glucose and urea present in 259 mL aqueous solution shows the osmotic pressure of 0.74 atm at 27^(@)C. Assuming solution to be dilute, select the correct statements:
Answer» <P> Percentage of urea in mixture is `17.6` Relative lowering in vapour pressureof this solution is `5.41 xx 10^(-4)` (c) The solution will boil at `100.015^(@)C`, if `K_(b)` of water is `0.5 K "molality"^(-1)` If glucose is replaced by same amount of sucrose, the solution will show higher osmotic pressure at `27^(@)C` Solution :Let `a` glucose, `b g` urea be present in `1 g` `:. a+b = 1` ….(1) Thus, `0.74 xx (250)/(1000) = ((1)/(180)+(b)/(60)) xx 0.0821 xx 300` ….(2) By eqs. (1) and (2), `b = 0.176, a = 0.824` `(P^(@)-P_(S))/(P^(@)) = (w xx M xx 1000)/(m xx W xx 1000)` `:.` Molality `= (P^(@)-P_(S))/(P^(@)) xx (1000)/(M)` or `(PI)/(ST) = (P^(@)-P_(S))/(P^(@)) xx (1000)/(M) ,(because M = m)` `:. (P^(@) -P_(S))/(P^(@)) = (0.74 xx 18)/(0.0821 xx 300 xx 1000)` `= 5.41 xx 10^(-4)` `Delta T_(b) = "molality" xx K_(b) = (pi)/(ST) xx K_(b)` `= (0.74)/(0.0821 xx 300) xx 0.5 = 0.015` `b.pt. = 100.015^(@)C` On replacing glucose `(mol. WT. 180)` by sucrose (mol wt. 342), `pi` will DECREASES as `pi prop (1)/(mol.wt)` On replacing glucose `(mol. wt. 180)` by `NaCl (mol. wt. 58.5), pi` will increases as `pi prop (1)/(mol. wt.) xx 2` for `NaCl`