1 g of a gaseous compound of boron and hydrogen occupies 0.820 L at 1 – InterviewSolution

InterviewSolution

1.	1 g of a gaseous compound of boron and hydrogen occupies 0.820 L at 1 atm and 3 ∘C. The compound is:(R=0.0820 L atm mol−1K−1; molar mass of H=1 g,B=10.8 g
Answer» $1 g$ of a gaseous compound of boron and hydrogen occupies $0.820 L$ at $1 atm$ and $3^{\circ} C$ . The compound is: $(R = 0.0820 {L atm mol}^{- 1} K^{- 1}; molar mass of H = 1 g, B = 10.8 g$

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