When limestone is heated, quicklime is formed according to the equation. CaCO3(s)⇌CaO(s)+CO2(g)The experiment was carried out in the temperature range 800−900oC, Equilibrium constant Kp follows the relation. log Kp=7.282−8500Twhere, T is temperature in Kelvin. At what temperature the decomposition will give CO2(g) at 1 atm?

When limestone is heated, quicklime is formed according to the equatio

1.	When limestone is heated, quicklime is formed according to the equation. CaCO3(s)⇌CaO(s)+CO2(g)The experiment was carried out in the temperature range 800−900oC, Equilibrium constant Kp follows the relation. log Kp=7.282−8500Twhere, T is temperature in Kelvin. At what temperature the decomposition will give CO2(g) at 1 atm?
Answer» When limestone is heated, quicklime is formed according to the equation. $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$ The experiment was carried out in the temperature range $800 - 900^{o} C,$ Equilibrium constant $K_{p}$ follows the relation. $l o g K_{p} = 7.282 - \frac{8500}{T}$ where, T is temperature in Kelvin. At what temperature the decomposition will give $C O_{2} (g)$ at 1 atm?