1.

1 g of a mixture of NaHCO_(3) and Na_(2)CO_(3) is heated to 150^(@)C. The volume of the CO_(2) produced at STP is 112.0 mL. Calculate the percentage of Na_(2)CO_(3) in the mixture (Na=23, C=12, O=16)

Answer»

20
46
84
16

Solution :`2NaHCO_(3) overset(150^(@)C)(rarr) Na_(2)CO_(3)+CO_(2)+H_(2)O`
`n_(NaHCO_(3))/n_(CO_(2))=2/1`
`n_(NaHCO_(3))=2n_(CO_(2))`
`=2xx112/22400=0.01` mole
`W_(NaHCO_(3))=0.01xx84=0.84 g`
`W_(Na_(2)CO_(3))=1.00-0.84=0.16 g`
`% Na_(2)CO_(3)=16`.


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