1.

1 g of charcoal adsorbs 100 ml of 0.5 M CH_(3)COOH to form a monolyer, and thereby the molarity ofCH_(3)COOH reduces to 0.49 M. Calculate the surface area of the charcoal adsorbed by each molecular of accetic acid. Surface area of charcoal =3.01xx10^(2)m^(2)g.

Answer»

Solution :100 ML of `0.5 M CH_(3)COOH` ontains `CH_(3)COOH=0.05` mole
After adsorption, `CH_(3)COOH` present `=0.049` mole
`therefore` Acetic acid adsorbed by 1 g charcoal `=90.05-0.049)` mole3 `=0.001` mole `=6.02xx10^(20)` molecules Surface area of 1 GOF charcoal `=3.01xx10^(2)m^(2)`
`therefore` Surface area of charcoal adsorbed by each MOLECULE `=(3.01xx10^(2)m^(2))/(6.02xx10^(20))=5xx10^(-19)m^(2)`


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