1.

1 g of metal, having no variable valency, produces1.67g of its oxide when heated in air. Its carbonate contains 28.57% of the metal. How much oxide will be obtained by heating 1g of the carbonate?

Answer»


Solution :`("MASS of metal")/("Mass of OXYGEN")=("Mass of metal in 1g of CARBONATE")/(x)`
i.e., x=0.1914g of oxygen
Mass of oxide `=0.2857+0.1914=0.4771g`


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