`1 g` steam at `100^@C` is passed in an insulating vessel having `1 g` ice at `0^@C`. Find the equilibrium composition of the mixture. (Neglecting heat capacity of the vessel).

`1 g` steam at `100^@C` is passed in an insulating vessel having `1 g`

1.	`1 g` steam at `100^@C` is passed in an insulating vessel having `1 g` ice at `0^@C`. Find the equilibrium composition of the mixture. (Neglecting heat capacity of the vessel).
Answer» Available heat from steam `mL = 1 xx 540 = 540 cal` Heat required for melting of ice and to rise its temperature to `100^@ C = m_(ice) L_(ice) + m_(water) S_(water) Delta theta` =`(1 xx 80) +[1 xx 1 xx(100 - 0)] = 180 cal` Let `m` be the mass of steam condensed, then `m xx 540 = 180 rArr m = (180)/(540) = (1)/(2) g` Final contents : Water = `1 + (1)/(3) = (4)/(3) g`, steam `= 1 - (1)/(3) = (2)/(3) g`.

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`1 g` steam at `100^@C` is passed in an insulating vessel having `1 g` ice at `0^@C`. Find the equilibrium composition of the mixture. (Neglecting heat capacity of the vessel).

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