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`1 gH_(2)` gas `STP` is expanded so that the volume is doubled. Hence, work done isA. `22.4 L-atm`B. `5.6 L-atm`C. `11.2 L-atm`D. `44.8 L-atm` |
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Answer» `V_(1) (volume of 1g H_(2)) = 11.2 L at STP` `V_(2)(volume of 1g H_(2)) = 22.4 L` ltbr. `:. W =P DeltaV = 11.2 L atm` |
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