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A monoatomic gas undergoes adiabatic process. Its volume and temperature are related as `TV^(P)` = constant. The value of p will be `{:((1),1.33,(2),1.67),((3),0.67,(4),0.33):}` |
Answer» For adiabatic process `TV^(gamma-1)` = constant for monoatomic gas `gamma` = 1.67 p = 1.67 - 1 = 0.67 `therefore "Ans"(3)` |
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