1.

When a polyatomic gas undergoes an adiabatic process, its tempertaure and volume are related by the equation `TV^(n) =` constant, the value of `n`will beA. `1.33`B. `0.33`C. `2.33`D. `1`

Answer» For adiabatic process
`TV^(gamma-1) =` constant
for poly atomis gas
`gamma = (4)/(3) = 1.33 (gamma = (C_(P))/(C_(V)))`
`n = 1.33 - 1 = 0.33`


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